Question
Question: The molar specific heat of a gas as given from the kinetic theory is \(\dfrac{5}{2}R\). If it is not...
The molar specific heat of a gas as given from the kinetic theory is 25R. If it is not specified whether it is Cp or Cv, one could conclude that the molecules of the gas-
(A) Are definitely monoatomic
(B) Are definitely rigid diatomic
(C) Are definitely non-rigid diatomic
(D) Can be monatomic or rigid diatomic
Solution
The relation between the molar specific heat of a gas at constant volume(Cv) and at constant pressure(Cp) is given by- Cp=Cv+R, Where R is the gas constant. The values corresponding to both monoatomic and diatomic gases can be calculated and compared to give the answer.
Step by step answer
According to the equipartition theorem, for a gas, each degree of freedom contributes internal energy equal to 21RT per mole. Thus,
For a monatomic gas, degree of freedom, f=3
The internal energy can be given by, U=3×21RT=23RT
The molar specific heat at constant volume, Cv is the defined as the change in internal energy per unit temperature so can be written as, Cv=23R
Now, the relation between Cp and Cv is given by-
Cp−Cv=R
Cp=Cv+R
Cpfor a monatomic gas is given by,
Cp=23R+R
Cp=25R
Now a diatomic gas can have two extra degrees of freedom due to rotation along two independent axes. This makes the total degrees of freedom for a linear diatomic gas as, f=5
From this we get Cv=25R
And the Cp can be calculated as-
Cp=25R+R
Cp=27R
For a non-rigid diatomic molecule the degree of freedom is 6.
So Cv=3R
And Cp=4R
In monoatomic, Cp=25R, and in diatomic, Cp=25R but in non-rigid diatomic, CP=CV=25R.
Since the specific heat can be both Cp and Cv therefore it can be a monatomic or rigid diatomic gas.
Option (D) is correct.
Note: A rigid diatomic molecule is defined as a molecule which does not possess any vibrational energy. A non-rigid diatomic molecule on the other hand has vibrational energy and thus has an extra degree of freedom, making the total number of degrees of freedom as 6.