Question
Question: The molar conductivity of the complex CoCl$_3$ · 4NH$_3$ · 2H$_2$O is found to be the same as that o...
The molar conductivity of the complex CoCl3 · 4NH3 · 2H2O is found to be the same as that of a 1 : 3 electrolyte. The structural formula of the compound is :

[Co(NH3)4(H2O)2]Cl3
[Co(NH3)4Cl (H2O)]Cl2H2O
[Co(NH3)4 (H2O)Cl2]ClH2O
[Co(NH3)4(H2O)2Cl]Cl2
[Co(NH3)4(H2O)2]Cl3
Solution
The molar conductivity of a complex is related to the number of ions it produces in solution. A 1:3 electrolyte dissociates into a total of 1+3=4 ions per formula unit. The given complex is CoCl3⋅4NH3⋅2H2O. We need to find the structural formula where the complex dissociates into 4 ions.
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Option A: [Co(NH3)4(H2O)2]Cl3: This complex dissociates into one complex cation [Co(NH3)4(H2O)2]3+ and three chloride anions Cl−. The total number of ions is 1+3=4. This corresponds to a 1:3 electrolyte.
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Option B: [Co(NH3)4Cl(H2O)]Cl2H2O: This complex dissociates into one complex cation [Co(NH3)4Cl(H2O)]2+ and two chloride anions Cl−. The total number of ions is 1+2=3. This corresponds to a 1:2 electrolyte.
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Option C: [Co(NH3)4(H2O)Cl2]ClH2O: This complex dissociates into one complex cation [Co(NH3)4(H2O)Cl2]+ and one chloride anion Cl−. The total number of ions is 1+1=2. This corresponds to a 1:1 electrolyte.
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Option D: [Co(NH3)4(H2O)2Cl]Cl2: This complex dissociates into one complex cation [Co(NH3)4(H2O)2Cl]2+ and two chloride anions Cl−. The total number of ions is 1+2=3. This corresponds to a 1:2 electrolyte.
Comparing the number of ions produced, only option Ⓐ produces 4 ions, which is consistent with a 1:3 electrolyte.