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Question: The molar conductivity of the complex CoCl$_3$ · 4NH$_3$ · 2H$_2$O is found to be the same as that o...

The molar conductivity of the complex CoCl3_3 · 4NH3_3 · 2H2_2O is found to be the same as that of a 1 : 3 electrolyte. The structural formula of the compound is :

A

[Co(NH3_3)4_4(H2_2O)2_2]Cl3_3

B

[Co(NH3_3)4_4Cl (H2_2O)]Cl2_2H2_2O

C

[Co(NH3_3)4_4 (H2_2O)Cl2_2]ClH2_2O

D

[Co(NH3_3)4_4(H2_2O)2_2Cl]Cl2_2

Answer

[Co(NH3_3)4_4(H2_2O)2_2]Cl3_3

Explanation

Solution

The molar conductivity of a complex is related to the number of ions it produces in solution. A 1:3 electrolyte dissociates into a total of 1+3=41+3=4 ions per formula unit. The given complex is CoCl34NH32H2O\text{CoCl}_3 \cdot 4\text{NH}_3 \cdot 2\text{H}_2\text{O}. We need to find the structural formula where the complex dissociates into 4 ions.

  • Option A: [Co(NH3)4(H2O)2]Cl3[\text{Co(NH}_3)_4(\text{H}_2\text{O})_2]\text{Cl}_3: This complex dissociates into one complex cation [Co(NH3)4(H2O)2]3+[\text{Co(NH}_3)_4(\text{H}_2\text{O})_2]^{3+} and three chloride anions Cl\text{Cl}^-. The total number of ions is 1+3=41 + 3 = 4. This corresponds to a 1:3 electrolyte.

  • Option B: [Co(NH3)4Cl(H2O)]Cl2H2O[\text{Co(NH}_3)_4\text{Cl}(\text{H}_2\text{O})]\text{Cl}_2\text{H}_2\text{O}: This complex dissociates into one complex cation [Co(NH3)4Cl(H2O)]2+[\text{Co(NH}_3)_4\text{Cl}(\text{H}_2\text{O})]^{2+} and two chloride anions Cl\text{Cl}^-. The total number of ions is 1+2=31 + 2 = 3. This corresponds to a 1:2 electrolyte.

  • Option C: [Co(NH3)4(H2O)Cl2]ClH2O[\text{Co(NH}_3)_4 (\text{H}_2\text{O})\text{Cl}_2]\text{ClH}_2\text{O}: This complex dissociates into one complex cation [Co(NH3)4(H2O)Cl2]+[\text{Co(NH}_3)_4 (\text{H}_2\text{O})\text{Cl}_2]^{+} and one chloride anion Cl\text{Cl}^-. The total number of ions is 1+1=21 + 1 = 2. This corresponds to a 1:1 electrolyte.

  • Option D: [Co(NH3)4(H2O)2Cl]Cl2[\text{Co(NH}_3)_4(\text{H}_2\text{O})_2\text{Cl}]\text{Cl}_2: This complex dissociates into one complex cation [Co(NH3)4(H2O)2Cl]2+[\text{Co(NH}_3)_4(\text{H}_2\text{O})_2\text{Cl}]^{2+} and two chloride anions Cl\text{Cl}^-. The total number of ions is 1+2=31 + 2 = 3. This corresponds to a 1:2 electrolyte.

Comparing the number of ions produced, only option Ⓐ produces 4 ions, which is consistent with a 1:3 electrolyte.