Question

The molar conductivity of a conductivity cell filled with $10$ moles of $20\, mL\, NaCl$ solution is $\Lambda_{ m 1}$ and that of $20$ moles another identical cell heaving $80 \, mL \, NaCl$ solution is $\Lambda_{ m 2}$, The conductivities exhibited by these two cells are same The relationship between $\Lambda_{ m 2}$ and $\Lambda_{ m 1}$ is

• A. $\Lambda_{ m 2}=2 \Lambda_{ m 1}$
• B. $\Lambda_{ m 2}=\Lambda_{ m 1} / 2$
• C. $\Lambda_{ m 2}=\Lambda_{ m 1}$
• D. $\Lambda_{ m 2}=4 \Lambda_{ m 1}$

Answer 1

Answer: (A)

$\Lambda_{ m 2}=2 \Lambda_{ m 1}$

Answer 2

Λm​=κ×M1000​
⇒Λm​∝M1​
Λm2​​Λm1​​​=M1​M2​​=2010​8020​​=41​×12​=21​
⇒Λm2​​=2Λm1​​