Question

The molal boiling point constant for water is 0.513⁰ C Kg/mol. When 0.1 mole of sugar is dissolved in 200mg of water, the solution boils under a pressure of one atmosphere at ___

Answer 1

The temperature at which a liquid's vapour pressure equals the pressure of the gas above it is known as the boiling point. A substance's boiling point is the temperature at which the vapour pressure of a liquid equals the pressure surrounding the liquid and the liquid transforms into a vapour. The boiling point of a liquid is affected by the surrounding atmospheric pressure.

Complete answer:
The basic equation for calculating a solution's boiling point is $\Delta T{\text{ }} = {\text{ }}m{K_b}$. The boiling-point elevation, meaning how much higher the boiling point of the solution is than that of the pure solvent, is referred to as $\Delta T{\text{ }}$. The temperature is measured in degrees Celsius. The molal boiling-point elevation constant is known as ${K_b}$. When one mole of solute is dissolved in one kg of solution, the boiling point rises. The molal boiling point elevation constant, ${K_b}$ is the proportionality constant.
Now from the question,
${K_b}$ = 0.513⁰ C Kg/mol
$\Delta T{\text{ }}$= 100⁰ C
Given, moles of sugar = 0.1
Mass of Water = 200 ml = 0.2 l
Molality is the number of moles of solute per kg of liquid which is a characteristic of a solution.
Using the formula Molality = mol/kg
Molality, $m = \dfrac{{0.1}}{{0.2}}$
m = 0.5
Now, substituting all the values,
$\Delta T{\text{ }} = {\text{ }}m{K_b}$
$\Delta T{\text{ }}$= ${T_b} - {T_b}^0$
${T_b} - {T_b}^0 = m{K_b}$
${T_b}$ - 100 = 0.5 x 0.513
${T_b}$= 100 + 0.256
${T_b}$= 100.256⁰ C

Note:
The basic equation for calculating a solution's boiling point is $\Delta T{\text{ }} = {\text{ }}m{K_b}$. The boiling-point elevation, meaning how much higher the boiling point of the solution is than that of the pure solvent, is referred to as $\Delta T{\text{ }}$. The temperature is measured in degrees Celsius. The molal boiling-point elevation constant is known as ${K_b}$. When one mole of solute is dissolved in one kg of solution, the boiling point rises. The molal boiling point elevation constant, ${K_b}$ is the proportionality constant.