Question

The minimum value of the twice differentiable function $f(x)=\int\limits_0^x e^{x-1} f^{\prime}(t) d t-\left(x^2-x+1\right) e^x, x \in R$, is :

• A. $-\frac{2}{\sqrt{ e }}$
• B. $-2 \sqrt{e}$
• C. $-\sqrt{ e }$
• D. $\frac{2}{\sqrt{e}}$

Answer 1

Answer: (A)

$-\frac{2}{\sqrt{ e }}$

Answer 2

The correct option is (A): $-\frac{2}{\sqrt{ e }}$