Question

The minimum value of $3\cos x + 4\sin x + 5$is

• A. 5
• B. 9
• C. 7
• D. 0

Answer 1

Answer: (D)

0

Answer 2

The minimum value of $3\cos x + 4\sin x$ is $- \sqrt{3^{2} + 4^{2}} = - 5$

Hence the minimum value of $3\cos x + 4\sin x + 5$

$= - 5 + 5 = 0$.