Question

The minimum pressure required to compress $600 \,dm^{3}$ of a gas at $1$ bar to $150\, dm^{3}$ at $40^{\circ}C$ is

• A. $4.0$ bar
• B. $0.2$ bar
• C. $1.0$ bar
• D. $2.5$ bar

Answer 1

Answer: (A)

$4.0$ bar

Answer 2

By Boyle's law

$P_{1}V_{1}=P_{2}V_{2}$
$1$ bar $\times 600dm^{3}=P_{2}\times 150\,dm^{3}$
$P_{2}=4$ bar