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Question: The mineral rutile is an oxide of titanium containing \(39.95\% \) oxygen and is isomorphous with ca...

The mineral rutile is an oxide of titanium containing 39.95%39.95\% oxygen and is isomorphous with cassiterite (SnO2Sn{O_2}). The atomic weight of titanium is :
A.) 68.1068.10
B.) 58.1058.10
C.) 48.1048.10
D.) 38.1038.10

Explanation

Solution

In this question, isomorphous compounds have the same crystal form. Therefore, the formula of oxide of tin will be (TiO2)(Ti{O_2}) that is similar to that of cassiterite. From the formula we can find the percentage of titanium because the percentage of oxygen is given.

Complete step by step answer:
In this question, two compounds are said to be isomorphous when they have almost similar crystalline structure , they are generally identical and have similar chemical formulas.
In the question, it is given that oxide of titanium is isomorphous with cassiterite that is (SnO2Sn{O_2}) . Therefore, as we know that isomorphous compounds have similar chemical formulas, as SnO2Sn{O_2} has two oxygen atoms in it therefore, the oxide of titanium will also have two atoms of oxygen and one atom of titanium. Therefore, the chemical formula of titanium oxide can be written as TiO2Ti{O_2}.
As in the question it is given that titanium oxide (TiO2Ti{O_2}) has 39.95%39.95\% of oxygen.
It means that in 100g100g of TiTi there is 39.95g39.95g of oxygen
Now, Molecular weight of TiO2Ti{O_2} =x+2×16g=x+32g = x + 2 \times 16g = x + 32g
Where xx is the mass of titanium
As we know that, x+32gx + 32g of TiO2Ti{O_2} will contain 32g32g of oxygen
1g of titanium=32x+32g of oxygen 100g of titanium=32x+32×100g of oxygen  1g{\text{ of titanium}} = \dfrac{{32}}{{x + 32}}g{\text{ of oxygen}} \\\ {\text{100g of titanium}} = \dfrac{{32}}{{x + 32}} \times 100g{\text{ of oxygen}} \\\
As we know that in 100g100g of TiTi there is 39.95g39.95g of oxygen. Therefore, we can rewrite the above equation as:
39.95=32x+32×100 x+32=32×10039.95 x+32=80.100 x=80.10032 x=48.10g  39.95 = \dfrac{{32}}{{x + 32}} \times 100 \\\ x + 32 = \dfrac{{32 \times 100}}{{39.95}} \\\ x + 32 = 80.100 \\\ x = 80.100 - 32 \\\ x = 48.10g \\\
Therefore, the required mass of titanium in titanium oxide (TiO2Ti{O_2}) is 48.10g48.10g.

Hence, option C.) is the correct answer.

Note:

Do not get confused between polymorphism and isomorphism. Polymorphism occurs when a particular substance exists in more than two crystalline form like- calcium carbonate exists in two crystalline structure and isomorphism occurs when two substance have similar crystalline structure like- TiO2,SnO2Ti{O_2},Sn{O_2}.