The middle term in the expansion of ((3x + a)^{5}) is . | MATH - GENERAL TERM, COEFFICIENT OF ANY POWER OF x | SolveeIt | Solveeit

Today, August 24

Question

The middle term in the expansion of $(3x + a)^{5}$ is .

A

$(x + 2a)^{3}$

B

$(a + b)^{m} = a^{m} + ma^{m - 1}b$

C

$+ \frac{m(m - 1)}{1.2}a^{m - 2}b^{2} + ....$

D

$b < a$

Answer

$(a + b)^{m} = a^{m} + ma^{m - 1}b$

Explanation

Solution

Middle term of $9C_{3}.\frac{1}{6^{3}}$ is $9C_{3}\left( \frac{3}{2} \right)^{3}$ .