The mid-pointegrals of sides AB, BC, CA of a D ABC are (6,... | MATH - POINTS RELATE TO TRIANGLE (ORTHOCENTRE,...) | SolveeIt | Solveeit

Today, October 3

Question

The mid-points of sides AB, BC, CA of a D ABC are

(6, –1), (– 4, – 3), (2, – 5) respectively then centroid of DABC is:

A

(4, 1)

B

$\left( \frac{4}{3},–3 \right)$

C

$\left( \frac{4}{3},3 \right)$

D

$\left( - \frac{4}{3},3 \right)$

Answer

$\left( \frac{4}{3},–3 \right)$

Explanation

Solution

centroid of D ABC = centroid of D DEF

D, E, F are mid points of AB, BC, CA respectively

\ centroid of D ABC

= $\left( \frac{6 - 4 + 2}{3},\frac{- 1 - 3 - 5}{3} \right)$

= $\left( \frac{4}{3}, - 3 \right)$