Question

The metre bridge shown is in balance position with $\frac{P}{Q} = \frac{l_{1}}{l_{2}}$ . If we now interchange the positions of galvanometer and cell, will the bridge work ? If yes, what will be balanced condition ?

• A. $ye, \frac{P}{Q} = \frac{l_{2} - l_{1}}{l_{2} + l_{1}}$
• B. no, no null point
• C. $yes, \frac{P}{Q} = \frac{l_{2}}{ l_{1}}$
• D. $yes, \frac{P}{Q} = \frac{l_{1}}{ l_{2}}$

Answer 1

Answer: (D)

$yes, \frac{P}{Q} = \frac{l_{1}}{ l_{2}}$

Answer 2

Yes, the bridge will work. For a balanced condition, the current drawn from the battery will be zero Also, $p \propto l_{1}$ and $Q \propto l_{2}$ Therefore, the condition $\frac{P}{Q}=\frac{l_{1}}{l_{2}}$ will remain same after interchanging the cell and galvanometer