Question

The metal surface is illuminated by a light of given intensity and frequency to cause photo emission. If the intensity of illumination is reduced to one- fourth of its original value, then the maximum kinetic energy of emitted photoelectrons will be –

• A. $\frac{1}{16}$th of original value
• B. Unchanged
• C. Twice the original value
• D. Four times the original value

Answer 1

Answer: (B)

Unchanged

Answer 2

K_max = hn – f

= unchanged