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Question: The median of the following data is: \(x:\)| \(10\)| \(20\)| \(30\)| \(40\)| \(50\) ---|---|-...

The median of the following data is:

x:x:10102020303040405050
f:f:2233223311

A. 3030
B. 4040
C. 3535
D. 3131

Explanation

Solution

To find the median of the given data, we will first arrange it in ascending or descending order. Then, find the cumulative frequency and finally find the median of the given data.
Cumulative frequency gives ranking after arranging in ascending or descending order. It is the sum of all the classes below it in distribution.

Complete step-by-step answer:
If the number of observations is odd
Then, median =(n2)thterm = {\left( {\dfrac{{\text{n}}}{{\text{2}}}} \right)^{{\text{th}}}}{\text{term}} .
If the number of observations is even
Then, median =(n + 12)th term = {\left( {\dfrac{{{\text{n + 1}}}}{2}} \right)^{{\text{th}}}}{\text{ term}} .
Complete step by step solution:
Given data:

x:x:10102020303040405050
f:f:2233223311

To find the median of the given data.
The first step is to arrange xx in ascending order or descending order. But in the given data it is already in ascending order.
Now, the total number of entities in the given data =2+3+2+3+1=11 = 2 + 3 + 2 + 3 + 1 = 11 i.e., odd.
Since in the given data frequency is given and it gives the number of times a number is repeating.
Therefore, we find cumulative frequency so that we can get the ranking of the terms after arranging them in ascending order.
So, cumulative frequency is given by:

xxffcfcf
10102222
2020332+3=52 + 3 = 5
3030225+2=75 + 2 = 7
4040337+3=107 + 3 = 10
50501110+1=1110 + 1 = 11

Now according to cumulative frequency 1010 is coming two times, then after 10 from third to the fifth position 2020 is coming, then after 20, from sixth to the seventh position 3030 is coming, then from eighth to the tenth position 4040 is coming and finally at eleventh position 5050 is coming.
So, the series becomes: 10,10,20,20,20,30,30,40,40,40,5010,10,20,20,20,30,30,40,40,40,50 .
Now, since a number of observations are odd.
So, median =(n + 12)thterm = {\left( {\dfrac{{{\text{n + 1}}}}{{\text{2}}}} \right)^{{\text{th}}}}{\text{term}}
i.e.,  = (11 + 12)thterm = 6th term{\text{ = }}{\left( {\dfrac{{{\text{11 + 1}}}}{{\text{2}}}} \right)^{{\text{th}}}}{\text{term = }}{{\text{6}}^{{\text{th}}}}{\text{ term}}
And from the obtained series sixth term is 3030
Hence, the median of the given data is 3030 .
So, the correct answer is “Option A”.

Note: Here, a number of terms are a summation of frequency and not the sum of xx .Do remember frequency gives the number of times a term is repeating while cumulative frequency gives ranking. Arranging the given data in ascending or descending order is necessary.