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Question: The mean proportional between two numbers is 28 and their third proportional is 224. Find the two nu...

The mean proportional between two numbers is 28 and their third proportional is 224. Find the two numbers.

Explanation

Solution

In algebra, a mean proportional is a number that comes between two numbers . We used a mean proportional formula which is ab=\sqrt {ab} = mean proportional. And the formula of third proportional ac=b2ac = {b^2}.

Complete step-by-step answer:
Mean proportional of two number is given in the question but numbers are not
So first we have to let a, b are the required numbers.
Formula of mean proportional
ab=\sqrt {ab} = mean proportional
ab=28\sqrt {ab} = 28
Now take the square both side
(ab)2=282{(\sqrt {ab} )^2} = {28^2}
ab=28.28ab = 28.28
ab=784ab = 784
So we can find the value of number a
a=784ba = \dfrac{{784}}{b} ……… equation (1)
We have the third proportional given in the question that is 224
The formula of third proportional
ac=b2ac = {b^2}
c=b2ac = \dfrac{{{b^2}}}{a}
Put the values
Here c is the third proportional
224=b2a224 = \dfrac{{{b^2}}}{a}
Now put the value of a
224=b2784b224 = \dfrac{{{b^2}}}{{\dfrac{{784}}{b}}}
Simplifying the equation
224=b2.b784224 = {b^2}.\dfrac{b}{{784}}
Multiply the R.H.S
224=b3784224 = \dfrac{{{b^3}}}{{784}}
Apply the cross-multiplication method
b3=224.784{b^3} = 224.784
b3={b^3} = 175616
b=3175616b{ = ^3}\sqrt {175616}
b=56b = 56
So here we the second number
We can find the first number a with the help of equation (1)
a=784ba = \dfrac{{784}}{b}
a=78456a = \dfrac{{784}}{{56}}
a=14a = 14
Hence, we have both the numbers
First is 14 and the second number is 56.

Note: In this type of question the most important point is calculation, always do the calculation carefully. We can check our answer by using a mean proportional method
Mean proportional =a.b\sqrt {a.b}
We have a = 14
And b = 56
After putting the values, we get
= 14.56\sqrt {14.56}
=784= \sqrt {784}
=28= 28
So here we get mean proportional that is already given in the question
Our answer is correct by alternative checking method.