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Question

Mathematics Question on Mean Deviation

The mean of five observations is 55 and their variance is 9.20.9.20. If three of the given five observations are 1,31, 3 and 88, then a ratio of other two observations is :

A

4:09

B

6:07

C

5:08

D

10:03

Answer

4:09

Explanation

Solution

Let two observations are x1&x2x_{1} \& x_{2}
mean =xi5=51+3+8+x1+x2=25=\frac{\sum x _{ i }}{5}=5 \Rightarrow 1+3+8+ x _{1}+ x _{2}=25
x1+x2=13\Rightarrow x _{1}+ x _{2}=13
variance (σ2)=xi2525=9.20\left(\sigma^{2}\right)=\frac{\sum x _{ i }^{2}}{5}-25=9.20
xi2=171\Rightarrow \quad \sum x_{i}^{2}=171
x12+x22=97\Rightarrow x _{1}^{2}+ x _{2}^{2}=97
by (1)&(2)(1) \&(2)
(x1+x2)22x1x2=97\left( x _{1}+ x _{2}\right)^{2}-2 x _{1} x _{2}=97
or x1x2=36x _{1} x _{2}=36
x1:x2=4:9\therefore x_{1}: x_{2}=4: 9