Solveeit Logo

Question

Question: The mean of a data is \(p\). If each observation is multiplied by \(3\) and then \(1\) is added to e...

The mean of a data is pp. If each observation is multiplied by 33 and then 11 is added to each result, then the mean of the new observations so obtained is
A. pp
B. 3p3p
C. p+1p + 1
D. 3p+13p + 1

Explanation

Solution

In this problem, the mean of the data is given. We are asked to find the new mean of the observation when each observation is multiplied by 33 and then 11 is added to each result. But here we don’t have the number of terms in data so we need to assume some value for the number of terms in data.

Formula used: m=sum of the termsnumber of termsm = \dfrac{{{\text{sum of the terms}}}}{{{\text{number of terms}}}}, where mm is mean.

Complete step by step solution:
Let us take the number of terms in data be nn.
Given that, mean =p = p
Since the number of terms in data be nn, so the sum of data =pn = pn
If each term is multiplied by 33, then the new sum of data becomes thrice, that is 3pn3pn
Also given that 11 is added in each term, since there are nn terms so if we add 11 for nn times then nn is added in sum, that is, New sum =3pn+n = 3pn + n
Mean of new observations m=sum of the termsnumber of termsm = \dfrac{{{\text{sum of the terms}}}}{{{\text{number of terms}}}}
m=3pn+nn\Rightarrow m = \dfrac{{3pn + n}}{n}
Take nn common in the numerator of above equation, we get
m=n(3p+1)n\Rightarrow m = \dfrac{{n(3p + 1)}}{n}
In the numerator and denominator nn get cancel each other,
m=3p+1\Rightarrow m = 3p + 1
Hence, the mean of new observation is 3p+13p + 1.

\therefore The answer is option (D)

Note: The way how we calculate mean in this problem is, the mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words, it is the sum divided by the count. Here the count is nn and the sum is 3pn+n3pn + n.