Question

The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then the mean of the remaining observations is

• A. 48
• B. 36
• C. 38
• D. none of these

Answer 1

Answer: (B)

36

Answer 2

The sum of all the 50 observations = 36 $\times$ 50 = 1800. Hence, the sum of remaining 48 observations = 1800- 42- 30 = 1728 = 48 $\times$ 36. So, the mean of remaining 48 observations is 36.