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Question: The mean of \[11\] observations is \[50\]. If the mean of the first six observations is \[49\] and t...

The mean of 1111 observations is 5050. If the mean of the first six observations is 4949 and that of the last six observations is 5252, which option is the sixth observation?
A. 5555
B. 5656
C. 5757
D. 5858

Explanation

Solution

We will be using the formula of mean which is the average of the numbers as shown below:
Mean=sum of the termsnumber of terms{\text{Mean}} = \dfrac{{{\text{sum of the terms}}}}{{{\text{number of terms}}}}
By using this formula, we will be calculating the sum of the terms.

Complete step-by-step solution:
Step 1: Total number of observations are
1111 and the mean is
5050. By using the formula of mean we get:
Mean=sum of the terms11\Rightarrow {\text{Mean}} = \dfrac{{{\text{sum of the terms}}}}{{11}}
By substituting the value of mean in the above expression we get:
50=sum of the terms11\Rightarrow 50 = \dfrac{{{\text{sum of the terms}}}}{{11}}
By taking 1111 into the LHS side of the above expression, we get:
50×11=sum of the terms\Rightarrow 50 \times 11 = {\text{sum of the terms}}
By doing the final multiplication in the above expression we get:
sum of the terms = 550\Rightarrow {\text{sum of the terms = 550}} …………………………. (1)
Step 2: The mean of the first six observations is 4949. By using the formula of mean we get:
Mean=sum of the terms6\Rightarrow {\text{Mean}} = \dfrac{{{\text{sum of the terms}}}}{6}
By substituting the value of mean in the above expression we get:
49=sum of the terms6\Rightarrow 49 = \dfrac{{{\text{sum of the terms}}}}{6}
By taking 66 into the LHS side of the above expression, we get:
49×6=sum of the terms\Rightarrow 49 \times 6 = {\text{sum of the terms}}
By doing the final multiplication in the above expression we get:
sum of the terms = 294\Rightarrow {\text{sum of the terms = 294}} …………………………. (2)
Step 3: The mean of the first six observation is
5252. By using the formula of mean we get:
Mean=sum of the terms6\Rightarrow {\text{Mean}} = \dfrac{{{\text{sum of the terms}}}}{6}
By substituting the value of mean in the above expression we get:
52=sum of the terms6\Rightarrow 52 = \dfrac{{{\text{sum of the terms}}}}{6}
By taking 66 into the LHS side of the above expression, we get:
52×6=sum of the terms\Rightarrow 52 \times 6 = {\text{sum of the terms}}
By doing the final multiplication in the above expression we get:
sum of the terms = 312\Rightarrow {\text{sum of the terms = 312}} …………………………. (3)
Step 4: Now the sixth observation will be equals to the subtraction of summation of the first and last six observation from the total sum as shown below:
Sixth observation = (sum of first six + sum of last six)sum of total observation\Rightarrow {\text{Sixth observation = }}\left( {{\text{sum of first six + sum of last six}}} \right) - {\text{sum of total observation}}
By substituting the values from expression (1), (2), and (3) in the above one we get:
Sixth observation = (294 + 312)550\Rightarrow {\text{Sixth observation = }}\left( {{\text{294 + 312}}} \right) - 550
Solving the brackets first by doing addition we get:
Sixth observation = (606)550\Rightarrow {\text{Sixth observation = }}\left( {606} \right) - 550
By doing the final subtraction in the above expression we get:
Sixth observation = 56\Rightarrow {\text{Sixth observation = 56}}

Option B is correct.

Note: Students should remember in solving these types of questions that for finding any middle term in the series when the mean is given for the rest then we need to subtract the sum of the series from the total of that series.