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Question: The mean lives for a-and b-decay of radioactive substance are 1620 years and 405 years respectively....

The mean lives for a-and b-decay of radioactive substance are 1620 years and 405 years respectively. In how much time will its 34th\frac{3}{4}thfraction will decay, if it simultaneously emits a-and b-particles –

A

449 years

B

399 years

C

109 years

D

9 years

Answer

449 years

Explanation

Solution

τ=τ1τ2τ1+τ2=1620×4052025=324\tau = \frac { \tau _ { 1 } \tau _ { 2 } } { \tau _ { 1 } + \tau _ { 2 } } = \frac { 1620 \times 405 } { 2025 } = 324 yearsT = 0.693

t = 224.5 years

t = 2T = 449 years