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Question

Physics Question on kinetic theory

The mean free path of collision of gas molecules varies with its diameter (d)(d) of the molecules as

A

d−1d^{-1}

B

d−2d^{-2}

C

d−3d^{-3}

D

d−4d^{-4}

Answer

d−2d^{-2}

Explanation

Solution

Mean free path of gas molecules
λ=λ1+λ2+…+λnn\lambda=\frac{\lambda_{1}+\lambda_{2}+\ldots+\lambda_{n}}{n}
λ=12πnd2\lambda =\frac{1}{\sqrt{2} \pi n d^{2}}
λ∝d−2\lambda \propto d^{-2}