Question

The mean energy of a molecule of an ideal gas is

• A. $2\, KT$
• B. $\frac{3}{2} KT$
• C. $KT$
• D. $\frac{1}{2} KT$

Answer 1

Answer: (B)

$\frac{3}{2} KT$

Answer 2

Average energy of a molecule of an ideal gas,
$E =\frac{E}{N}=\frac{3}{2} K T$