Question

The mean distance between the atoms of iron is $3 \times 10^{- 10}m$ and interatomic force constant for iron is 7 N/m. The Young’s modulus of elasticity for iron is

• A. $2.33 \times 10^{5}N/m^{2}$
• B. $23.3 \times 10^{10}N/m^{2}$
• C. $233 \times 10^{10}N/m^{2}$
• D. $2.33 \times 10^{10}N/m^{2}$

Answer 1

Answer: (D)

$2.33 \times 10^{10}N/m^{2}$

Answer 2

$Y = \frac{k}{r_{o}} = \frac{7}{3 \times 10^{- 10}} = 2.33 \times 10^{10}N/m^{2}$.