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Question

Mathematics Question on Probability

The mean deviation from the mean of the AP: a,a+d, a+2d,..., a+2nd, is

A

n(n+1)d

B

n(n+1)2n+1d\frac{n(n+1)}{2n+1}d

C

n(n+1)2nd\frac{n(n+1)}{2n}d

D

n(n1)2n+1d\frac{n(n-1)}{2n+1}d

Answer

n(n+1)2n+1d\frac{n(n+1)}{2n+1}d

Explanation

Solution

The correct answer is(B): n(n+1)2n+1d\frac{n(n+1)}{2n+1}d