Question

The maximum wavelength of radiations emitted at 900 K is $4 \mu m$ . What will be the maximum wavelength of radiations emitted at 1200 K

• A.
• B.
• C. $1 \mu m$
• D. $1 m$

Answer 1

Answer: (A)

Answer 2

$\frac { \lambda _ { 2 } } { \lambda _ { 1 } } = \frac { T _ { 1 } } { T _ { 2 } } \Rightarrow \lambda _ { 2 } = \frac { T _ { 1 } } { T _ { 2 } } \times \lambda _ { 1 } = \frac { 900 } { 1200 } \times 4 = 3 \mu \mathrm {~m}$