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Question: The maximum wavelength of Lyman series is-...

The maximum wavelength of Lyman series is-

A

1R2\frac{1}{R^{2}}

B

1RC\frac{1}{RC}

C

cR\frac{c}{R}

D

43R\frac{4}{3R}

Answer

43R\frac{4}{3R}

Explanation

Solution

1λ\frac{1}{\lambda} = R[1n12–1n22]\left\lbrack \frac{1}{n_{1}^{2}}–\frac{1}{n_{2}^{2}} \right\rbrack

1λ.max⁡\frac{1}{{\lambda.}_{\max}} = R [112–122]\left\lbrack \frac{1}{1^{2}}–\frac{1}{2^{2}} \right\rbrack or 1λ.max⁡\frac{1}{{\lambda.}_{\max}} = R [1–14]\left\lbrack 1–\frac{1}{4} \right\rbrack

or lmax. = 43R\frac{4}{3R}