Question

The maximum wavelength of Brackett series of hydrogen atom will be______$A^\circ$

• A. 35890
• B. 14440
• C. 62160
• D. 40400

Answer 1

Answer: (D)

40400

Answer 2

$RZ^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) = \frac{1}{\lambda}$ $Where \, n_1$ = 4 ; $n_2$ = 5