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Question

Physics Question on projectile motion

The maximum vertical height to which a man can throw a ball is 136m136 \,m The maximum horizontal distance upto which he can throw the same ball is:

A

68m68\, m

B

136m136\, m

C

192m192\, m

D

272m272\, m

Answer

272m272\, m

Explanation

Solution

Hmax=v22g=136  mH_{max}=\frac{v_2}{2g}=136\;m

Rmax=v2g=2HmaxR_{max}=\frac{v^2}{g}=2H_{max}

=2(136)2(136)

= 272272 mm

Hence, the correct option is (D):272  m\text{Hence, the correct option is (D):}272\;m