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Question: The maximum vertical distance through which a full dressed astronaut can jump on the Earth is 0.5 m....

The maximum vertical distance through which a full dressed astronaut can jump on the Earth is 0.5 m. Estimate the maximum vertical distance through which he can jump on the moon, which has a mean density 23rd\dfrac{2}{3}rd that of the Earth and radius one quarter that of the Earth.
A. 1.5m
B. 3m
C. 6m
D. 7.5m

Explanation

Solution

Hint: Planets and stars have their properties such as their size, mass and density. These properties determine the gravitational pull of a planet. Moon is a star of the Earth and is smaller in size than the Earth. The density of the moon is 60% as that of the Earth. Therefore the gravitational potential energy on the Moon is less than that on the Earth.

Complete step-by-step answer:
Step I:
Let the astronaut jump with an initial velocity ‘u’ and a final speed of ‘v’. Let ‘h’ be the maximum height he jumps to and ‘g’ be acceleration due to gravity.

Step II:
Then by equation of motion
v2=u22gh{v^2} = {u^2} - 2gh

Step III:
If the jumping speed on the Earth and moon is same then
h1gh \propto \dfrac{1}{g}
And the gravitational acceleration on a planetg=GMR2g = \dfrac{{GM}}{{{R^2}}}---(i)
M is mass of Earth and M=43πρR3M = \dfrac{4}{3}\pi \rho {R^3}---(ii)

Step IV:
Substituting value of M from equation (ii) to (i)
g=G43ρπR3R2g = \dfrac{{G\dfrac{4}{3}\rho \pi {R^3}}}{{{R^2}}}
Where G= Gravitational constant
R=Radius and ρ=\rho = density
g=43πρGRg = \dfrac{4}{3}\pi \rho GR
Value of 43πG\dfrac{4}{3}\pi G is constant.
Therefore, gρRg \propto \rho R.

Step V:
Value of ‘g’ on moon is, gm=ge6{g_m} = \dfrac{{{g_e}}}{6}
Since astronauts have energy to jump only 0.5m on Earth. Therefore on moon,
P.E.moon=P.E.EarthP.E{._{moon}} = P.E{._{Earth}}
mgmhm=mgehem{g_m}{h_m} = m{g_e}{h_e}
gmhm=gehe{g_m}{h_m} = {g_e}{h_e}
hm=gegmhe{h_m} = \dfrac{{{g_e}}}{{{g_m}}}{h_e}
hm=6×he{h_m} = 6 \times {h_e}
hm=6×12{h_m} = 6 \times \dfrac{1}{2}
hm=3m{h_m} = 3m

Step VI:
Maximum vertical distance he can jump on moon is = 3m
Option B is the right answer.

Note: Whenever a person jumps, he tries to move out of the influence of gravitational force. But since the gravitational force on the moon is 17% that of Earth. So using the same force as that of Earth, one can jump even much higher on the moon than that on the Earth.