Question

The maximum velocity to which a proton can be accelerated in a cyclotron of $10\, MHz$ frequency and radius $50\, cm$ is

• A. $6.28 \times 10^{8}\,m/s$
• B. $3.14 \times 10^{8}\,m/s$
• C. $6.28 \times 10^{7}\,m/s$
• D. $3.14 \times 10^{7}\,m/s$

Answer 1

Answer: (D)

$3.14 \times 10^{7}\,m/s$

Answer 2

The motion of proton in magnetic field will be circular
$\therefore V=2\pi rf$
$=2\times3.14\times50\times10^{-2}\times10\times10^{6}$
$=3.14\times10^{7} m/s$