Question

The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is :

• A. 0.01 s
• B. 10 s
• C. 0.1 s
• D. 100 s

Answer 1

Answer: (A)

0.01 s

Answer 2

The maximum velocity of a particle performing SHM is given by v = A$\omega$ , where A is the amplitude and $\omega$ is the angular frequency of oscillation. $\therefore \, \quad 4.4 =\left(7\times10^{-3}\right)\times2\pi/T$ $\Rightarrow \, \quad T=\frac{7\times10^{-3}}{4.4}\times\frac{2\times22}{7}=0.01 s$