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Question

Mathematics Question on Linear Programming Problem

The maximum value of z=3x+4yz = 3x + 4y subject to the condition x+y40,x+2y60,x,y0x + y \le 40, x + 2y \le 60, x,y \ge 0 is

A

130

B

120

C

40

D

140

Answer

140

Explanation

Solution

Obviously, z=3x+4yz = 3x + 4y will be maximum at (20,20)(20,\, 20) \therefore Max z=3?20+4?20=60+80=140z = 3 ? 20 + 4 ? 20 = 60 + 80 = 140