Solveeit Logo

Question

Question: The Maximum value of \( 4{\sin ^2}x + 3{\cos ^2}x \) is \( A - 3 \) \( B - 4 \) \( C - 5 ...

The Maximum value of 4sin2x+3cos2x4{\sin ^2}x + 3{\cos ^2}x is
A3A - 3
B4B - 4
C5C - 5
D7D - 7

Explanation

Solution

Hint : In order to solve the Trigonometric Numerical , we need to know all the Identities by heart in order to solve the numerical . First step is to identify the type of identity to be used based on the trigonometric function given in the question. Since there are several identities for a single function, the next step is to decide which particular identity would suffice in order to solve the problem. It is also Advisable to Know the Maximum value , Minimum value and value for π6&60\dfrac{\pi }{6}\& {60^ \circ } for all trigonometric functions

Complete step-by-step answer :
From the above question we can figure it out that we have to make use of the Trigonometry identities in order to find the correct answer. Since the problem involves sinx\sin x & cosx\cos x we will have to make use of identity
sin2θ+cos2θ=1..........(1){\sin ^2}\theta + {\cos ^2}\theta = 1..........(1)
Given : 4sin2x+3cos2x4{\sin ^2}x + 3{\cos ^2}x
Restructuring Equation1Equation1 :
cos2θ=1sin2θ..........(2){\cos ^2}\theta = 1 - {\sin ^2}\theta ..........(2)
Substituting value of cos2θ{\cos ^2}\theta from Equation2Equation2 into the given problem
We are replacing θ\theta with xx , since the question consists of xx . There is no compulsion on using θ\theta with Trigonometric functions.
4sin2x+3×(1sin2x)\Rightarrow 4{\sin ^2}x + 3 \times (1 - {\sin ^2}x)
On simplifying the above equation and on opening the brackets we will get the following equation
4sin2x+33sin2x........(3)\Rightarrow 4{\sin ^2}x + 3 - 3{\sin ^2}x........(3)
Further Simplifying the Equation3Equation3 in order to bring it to non-reducible form
sin2x+3.......(4)\Rightarrow {\sin ^2}x + 3.......(4)
Now remembering the properties of sinx\sin x we can say that the value of sinx\sin x ranges from 1- 1 to 11 .
Thus the maximum value of sinx\sin x will always be 11 . Thus the maximum value of sin2x{\sin ^2}x will be 11 .
\therefore Substituting Maximum Value of sin2x{\sin ^2}x Equation4Equation4
Final answer on substituting would be 44 .
Thus the maximum value of 4sin2x+3cos2x4{\sin ^2}x + 3{\cos ^2}x is 44 .
From the given options, the correct option is OptionBOptionB which has a value of 44 .
So, the correct answer is “Option B”.

Note : It is also Advisable to Know the Maximum value , Minimum value and value π6&60\dfrac{\pi }{6}\& {60^ \circ } for all trigonometric functions. This is because in almost all the sums these are the standard angles based on which the questions are asked. Apart from these , memorizing the formulas and the relationship between various trigonometric functions is extremely vital.