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Question: The maximum sum of the series <img src="https://cdn.pureessence.tech/canvas_161.png?top_left_x=768&t...

The maximum sum of the series is.

A

310

B

300

C

320

D

None of these

Answer

310

Explanation

Solution

nthn ^ { t h } term of the series is 20+(n1)(23)20 + ( n - 1 ) \left( - \frac { 2 } { 3 } \right).

For sum to be maximum, nthn ^ { t h } term 0\geq 0

\Rightarrow 20+(n1)(23)020 + ( n - 1 ) \left( - \frac { 2 } { 3 } \right) \geq 0 \Rightarrow n31n \leq 31

Thus the sum of 31 terms is maximum and is equal to

312[40+30×(23)]=310\frac { 31 } { 2 } \left[ 40 + 30 \times \left( - \frac { 2 } { 3 } \right) \right] = 310.