Question

The maximum speed of a particle executing S.H.M. is $1m/s$ and its maximum acceleration is$1.57m/sec^{2}$. The time period of the particle will be

• A. $\frac{1}{1.57}\sec$
• B. 1.57 sec
• C. 2 sec
• D. 4 sec

Answer 1

Answer: (D)

4 sec

Answer 2

Given max velocity $\omega a = 1$and maximum acceleration

$\omega^{2}a = 1.57$

$\therefore\frac{\omega^{2}a}{\omega a} = 1.57 \Rightarrow \omega = 1.57$ $\Rightarrow \frac{2\pi}{T} = 1.57 \Rightarrow T = 4$