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Question

Physics Question on projectile motion

The maximum range of a projectile is 100m100\,m . The maximum height reached by it is

A

100m100\,m

B

25m25 \,m

C

200m200 \,m

D

75m75 \,m

Answer

25m25 \,m

Explanation

Solution

Rmax=u2g=100mR_{\max }=\frac{u^{2}}g=100\,m
The range of the projectile is maximum for the angle of projection θ=45\theta =45^{\circ} .
When the range is maximum the height attained by a projectile is,
H=u24g=1004=25mH=\frac{u^{2}}4{\,g}=\frac{100}{4}=25\,m