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Question

Physics Question on projectile motion

The maximum range of a projectile fired with some initial velocity is found to be 1000 metre, in the absence of wind and air resistance. The maximum height h reached by this projectile is

A

250 m

B

500 m

C

1000 m

D

2000 m

Answer

250 m

Explanation

Solution

Rmax=u2g=1000mR_{max} = \frac{u^2}{g} = 1000 m
(R is maximum when θ\theta = 45?)
H=u2sin2θ2g=u22g×sin245H = \frac{u^2 \, \sin^2 \, \theta}{2g} = \frac{u^2}{2g} \times \sin^2 \, 45^\circ
=10004=250m= \frac{1000}{4} = 250 \, m
So, the correct option is (A): 250 m.