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Question: The maximum probability of finding an electron in the \( {d_{xy}} \) orbital is: A. along the x-ax...

The maximum probability of finding an electron in the dxy{d_{xy}} orbital is:
A. along the x-axis
B. along the y-axis
C. at an angle of 450{45^0} from the x and y axis
D. at an angle of 900{90^0} from the x and y axis

Explanation

Solution

The simplest classical model of the hydrogen atom is one in which the electron moves in a circular planar orbit about the nucleus as previously discussed and as illustrated.

Complete step by step solution:
The lobes of dxy{d_{xy}} orbital are oriented in between the axes at an angle 450{45^0} . so the finding electron in an dxy{d_{xy}} orbital is maximum at an angle of 450{45^0} from the x and y axis.
The precise force vector M in this figure appears at a point with regard to some subjective hub in space. Expecting for the second that we can by one way or another actually characterize such a hub, at that point in the traditional model of the molecule there ought to be an endless number of qualities feasible for the part of the precise energy vector along this pivot.
The penetration of a potential wall by the electron, into regions of negative kinetic energy, is known as "tunneling." Classically a particle must have sufficient energy to surmount a potential barrier. In quantum mechanics, an electron may tunnel into the barrier (or through it, if it is of finite width). Tunneling will not occur unless the barrier is of finite height. In the example of the H atom, the potential well is infinitely deep, but the energy of the electron is such that it is only a distance En from the top of the well.
Hence correct option is (C).

Note:
The point q is another illustration of an actual amount which in a traditional framework may accept any worth, yet which in a quantum framework may take on just certain discrete qualities. You need not acknowledge this outcome on trust.