Question

The maximum potential energy of a block executing simple harmonic motion is $25 J$ A is amplitude of oscillation At $A / 2$, the kinetic energy of the block is

• A. $18.75 J$
• B. $37.5 J$
• C. $9.75 J$
• D. $12.5 J$

Answer 1

Answer: (A)

$18.75 J$

Answer 2

umax​=21​mω2A2=25J
KE at 2A​=21​mv12​=21​mω2(A2−4A2​)
KE=21​mω243A2​=43​(21​m2A2)
KE=43​×25=18.75J