Question

The maximum number of stereoisomer exist for the compound

• A. 6
• B. 8
• C. 10
• D. 16

Answer 1

Answer: (C)

10

Answer 2

For symmetrical molecule with even no. of chiral center total no. of stereoisomer = 2^n–1 + $2^{\frac{n}{2}–1}$

where n = no. of chiral center