Question

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double-slit experiment is –

• A. Three
• B. Five
• C. Infinite
• D. Zero

Answer 1

Answer: (B)

Five

Answer 2

d = 2l

Path difference D = d sinq = 2l sinq

Maximum path difference D_max = 2l

So path difference for maxima

2\lambda,\lambda,0,\lambda,2\lambda \end{matrix}$$