Question

The maximum number of electrons, present in an orbit that is represented by azimuthal quantum number $(l)=3$, will be

• A. $8$
• B. $2$
• C. $14$
• D. $6$

Answer 1

Answer: (D)

$6$

Answer 2

When azimuthal quantum number is 3
$\, \, \, \, \, \, \, \, \, \, \, \,$m = (2l + 1)
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \,$l = 3
$\, \, \, \, \, \, \, \, \, \, \, \, m = (2 \times 3 + 1)$
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \,$= 7 orbitals
then total values of m = $(2 \times 3 + 1) = 7$ orbitals. We know that, one orbital contains two electrons. Hence, total number of electrons = $7 \times 2 = 14$
Alternative Total number of electrons = 4l + 2
$= 4 \times 3 + 2 = 12+ 2 = 14 electrons$