Question

The maximum number of electrons in N shell is:
A. 2
B. 8
C. 18
D. 32

Answer 1

Following the request: KLMN, N is the fourth shell of a particle. The quantity of electrons in a shell relies upon the component, its oxidation state and its electronic state. Considering an electrically impartial molecule in the ground express, the components in H-Ar range have no electron in the N shell (K, L and M shells are being filled).

Complete step by step answer:
K is the primary component where N shell starts to be filled ($\left[ Ar \right]4{{S}^{2}}$arrangement) trailed by Ca ($\left[ Ar \right]4{{S}^{2}}$)The following components are progress metals ($Sc-Zn$) which, attributable to the filling of 3d orbitals, doesn't have its N shell changed (aside from by several special cases). After Zn, in the $Ga-Kr$ range, the N shell is loaded up with third to eighth electrons which possess 4p orbitals. The following two components, Rb Sr, actually have 8 electrons in the N shell since 5s orbitals are filled. At that point 4d orbitals are filled across $Y-Cd$change metals, developing N shells from 9 to 18 electrons. In the following components ($(In-Xe)$) 5p orbitals are filled and N shell stays unaltered, a similar happening to Cs and Ba where 6s orbitals are filled.

The N shells are filled again in the lanthanide arrangement($(La/Yb)$) where 4f orbitals are involved. In the last component of this arrangement ($Yb$) N shell is full, with 32 electrons, and no further electron can be added to this shell.

**So, the correct option is D. 32

Note:**
The fourth shell of electrons surrounding the nucleus of an atom contains, when filled, 32 electrons having principal quantum number 4.