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Question: The maximum intensity in case of interference of n identical waves, each of intensity I<sub>0</sub>,...

The maximum intensity in case of interference of n identical waves, each of intensity I0, if the interference is (i) coherent and (ii) incoherent respectively are

A

n2I0,nI0n^{2}I_{0},nI_{0}

B

nI0,n2I0nI_{0},n^{2}I_{0}

C

nI0,I0nI_{0},I_{0}

D

n2I0,(n1)I0n^{2}I_{0},(n - 1)I_{0}

Answer

n2I0,nI0n^{2}I_{0},nI_{0}

Explanation

Solution

In case of interference of two wave I=I1+I2+2I1I2cosφI = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}}\cos\varphi

(i) In case of coherent interference φ does not vary with time and so I will be maximum when cosφ=max=1\cos\varphi = \max = 1

i.e. (Ico12I1I2I1I22max({Ic{o_{1}}_{2}\sqrt{I_{1}I_{2}}\sqrt{I_{1}}{\sqrt{I_{2}}}^{2}}_{\max}

So for n identical waves each of intensity

I0 (IcoI0I02I0220max({Ico\sqrt{I_{0}}{\sqrt{I_{0}}}^{2}{{{\sqrt{I_{0}}}^{2}}^{2}}_{0}}_{\max}

(ii)In case of incoherent interference at a given point, φ varies randomly with time, so (cosφ)av=0(\cos\varphi)_{av} = 0 and hence

(IR)Inco=I1+I2(I_{R})_{Inco} = I_{1} + I_{2}

So in case of n identical waves (IR)Inco=I0+I0+.......=nI0(I_{R})_{Inco} = I_{0} + I_{0} + ....... = nI_{0}