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Question: The maximum energy in the thermal radiation from a hot source occurs at a wavelength of \(11 \times...

The maximum energy in the thermal radiation from a hot source occurs at a wavelength of 11×105 cm11 \times 10 ^ { - 5 } \mathrm {~cm} . According to Wein's law, the temperature of the source (on Kelvin scale) will be nn times the temperature of another source (on Kelvin scale) for which the wavelength at maximum energy is nn is

A

2

B

4

C

12\frac { 1 } { 2 }

D

1

Answer

12\frac { 1 } { 2 }

Explanation

Solution

T1T2=λm2λm1=5.5×10511×105=12\frac { T _ { 1 } } { T _ { 2 } } = \frac { \lambda _ { m _ { 2 } } } { \lambda _ { m _ { 1 } } } = \frac { 5.5 \times 10 ^ { 5 } } { 11 \times 10 ^ { 5 } } = \frac { 1 } { 2 }n=12n = \frac { 1 } { 2 } .