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Question

Physics Question on Gravitation

The maximum and minimum distance of a comet from the sun are 8×1012m 8\times 10^{12}m and 1.6×1012m 1.6\times 10^{12}m . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when farthest?

A

12

B

60

C

112

D

6

Answer

12

Explanation

Solution

According to law of conservation of angular momentum mυ1r1=mυ2r2m{{\upsilon }_{1}}{{r}_{1}}=m{{\upsilon }_{2}}{{r}_{2}} or υ1=υ2r2r1{{\upsilon }_{1}}=\frac{{{\upsilon }_{2}}{{r}_{2}}}{{{r}_{1}}} =60×1.6×10128×1012=12m/s=\frac{60\times 1.6\times {{10}^{12}}}{8\times {{10}^{12}}}=12\,m\text{/}s