Question

The masses of the wire of copper are in the ratio of 1 : 3 : 5 and their lengths are in the ratio of 5 : 3 : 1. The ratio of their electrical resistance is-

• A. 1 : 3 : 5
• B. 5 : 3 : 1
• C. 1 : 15 : 125
• D. 125 : 15 : 1

Answer 1

Answer: (C)

1 : 15 : 125

Answer 2

R µ $\frac{\mathcal{l}^{2}}{m}$ ; R₁ : R₂ : R₃ : : $\frac{1}{5}$ : $\frac{9}{3}$ : $\frac{25}{1}$

: : 1 : 15 : 125