Question

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV).

• A. 28.4 MeV
• B. 20.8 MeV
• C. 27.3 MeV
• D. 14.2 MeV

Answer 1

Answer: (A)

28.4 MeV

Answer 2

B.E.= ∆mc²$= \lbrack 2(1.0087 + 1.0073) - 4.0015\rbrack = 28.4\mspace{6mu} MeV$