Question

The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of $_2^4 He$ is (Given: helium nucleus mass ≈ 4.0015 u)

• A. 0.0305 J
• B. 0.0305 erg
• C. 28.4 MeV
• D. 0.061 u

Answer 1

Answer: (C)

28.4 MeV

Answer 2

Binding Energy of $_2^4 He$:
BE = ∆m × 931
BE = [2(1.0087 + 1.0073) – 4.0015] × 931
BE = [4.032 - 4.0015] × 931
BE = 0.0305 × 931
BE = 28.4 MeV

So, the correct option is (C): 28.4 MeV