Question

The mass of potassium dichromate crystals required to oxidise $750\, cm^3$ of 0.6 M Mohr's salt solution is : (Given molar mass potassium dichromate = 294, Mohr's salt = 392)

• A. 0.45 g
• B. 22.05 g
• C. 2.2 g
• D. 0.49 g

Answer 1

Answer: (B)

22.05 g

Answer 2

$0.6\times0.75\times1 = \frac{w}{294}\times6$ $w = 22.05\, g$