Question

The mass of gas obtained when 1.5 × 10^–3 moles of MnO₄^– oxidised 1.2 mg of H₂O₂ in acidic medium is-

• A. 2.2 mg
• B. 1.12 mg
• C. 3.2 mg
• D. 0.56 mg

Answer 1

Answer: (B)

1.12 mg

Answer 2

H₂O₂ + MnO₄^– ¾® Mn⁺² + O₂

$\left( \frac{1.2}{34} \times 2 \right)$meq (1.5 × 5)meq

(limiting reagent )

m moles of O₂ = $\frac{1.2 \times 2}{34}$× $\frac{1}{2}$ = $\frac{1.2}{34}$ m mol

mass of O₂ = $\frac{1.2}{34}$ × 32 mg

= 1.12 mg